Random IFS

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For example, suppose we specify the resolution corresponding to addresses of length N = 3 and we start with the point (x₀, y₀) with address 1^infinity.

To the specified resolution, (x₀, y₀) lies in the region with address 111.

If T₂ is the first transformation applied, then resulting point (x₁, y₁) = T₂(x₀, y₀) lies in the region with address 211.

If T₃ is the next transformation applied, then resulting point (x₂, y₂) = T₃(x₁, y₁) lies in the region with address 321.

If T₄ is the next transformation applied, then resulting point (x₃, y₃) = T₄(x₂, y₂) lies in the region with address 432.

Continuing will fill in all the 4³ regions of address length 3.

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